The specific heat C_v at constant volume of a monatomic gas at low pressure is proportional to Tⁿ where the exponent n is:

Question

Quizplus · Accepted Answer

According to the given equation, C_v is proportional to Tⁿ. If we differentiate both sides of the equation with respect to T, we get: d(C_v )/dT = ⁿ + nTⁿ / T Since the gas is monatomic, the molar specific heat at constant volume is given by: C_v = 3/2R where R is the gas constant. Substituting this in the above equation, we get: d(3/2R)/dT = ⁿ + nT(3/2R)/T 0 = ⁿ + 3/2nR Solving for n, we get: n = 0 Therefore, the best choice is B, as n equals 0.

The Specific Heat Cv at Constant Volume of a Monatomic

The Specific Heat C_v at Constant Volume of a Monatomic