The sound intensity 5.0 m from point source is 0.50 W/m². The power output of the source is: A) 39 W B) 160 W C) 266 W D) 320 W E) 390 W

Question

Quizplus · Accepted Answer

The relationship between sound intensity and power output for a point source is given by the formula:
I = P/(4πr^2)
where I is sound intensity, P is power output, and r is distance from the source.

Rearranging the formula to solve for P, we get:
P = I * (4πr^2)

Substituting the given values, we get:
P = 0.50 * (4π*5^2)
P = 39.27 W

Therefore, the closest answer choice is B) 160 W.

The Sound Intensity 5