A piano wire has length L and mass M. If its fundamental frequency is f, its tension is: A) 2Lf/m B) 4MLf C) 2Mf²/L D) 4f²L³/M E) 4LMf²

Question

Quizplus · Accepted Answer

The fundamental frequency of a stretched string is given by $ f = \frac{1}{2L} \sqrt{\frac{T}{\mu}} $, where $ T $ is the tension and $ \mu = \frac{M}{L} $ is the linear mass density. Solving for $ T $, we get $ T = 4LMf^2 $.

A Piano Wire Has Length L and Mass M