The coefficient of static friction between a certain cylinder and a horizontal floor is 0.40. If the rotational inertia of the cylinder about its symmetry axis is given by I = (1/2)MR², then the maximum acceleration the cylinder can have without sliding is: A) 0.1 g B) 0.2 g C) 0.4 g D) 0.8 g E) g

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The Answer of The coefficient of static friction between a certain cylinder and a horizontal floor is 0.40. If the rotational inertia of the cylinder about its symmetry axis is given by I = (1/2)MR², then the maximum acceleration the cylinder can have without sliding is: A) 0.1 g B) 0.2 g C) 0.4 g D) 0.8 g E) g

The Coefficient of Static Friction Between a Certain Cylinder and a Horizontal