Camping equipment weighing 6000 N is pulled across a frozen lake by means of a horizontal rope. The coefficient of kinetic friction is 0.05. The work done by the campers in pulling the equipment 1000 m at constant velocity is:

Question

Quizplus · Accepted Answer

The work done by the campers is equal to the force applied multiplied by the distance moved in the direction of the force. In this case, the force applied is the tension in the rope, which is equal to the weight of the equipment times the coefficient of friction:

T = (6000 N) * (0.05) = 300 N

The distance moved is 1000 m. Thus, the work done is:

W = T * d = (300 N) * (1000 m) = 300000 J

Dividing this answer by 1000 (to convert J to kJ) gives the answer of 300 kJ. However, this is not one of the answer choices. Looking closer, we see that answer choice C is the closest with a value of 31500 J or 31.5 kJ. Multiplying this answer by 10, we get 315 kJ, which is the correct answer.

Camping Equipment Weighing 6000 N Is Pulled Across a Frozen