A particle goes from x = -2 m, y = 3 m, z = 1 m to x = 3 m, y = -1 m, z = 4 m. Its displacement is:

Question

Quizplus · Accepted Answer

To find the displacement, we subtract the initial position vector from the final position vector: <3,-1,4> - <-2,3,1> = <5,-4,3> The magnitude of this vector is: sqrt((5)^2+(-4)^2+(3)^2) = sqrt(50+16+9) = sqrt(75) = 5sqrt(3) Therefore, the displacement is 5sqrt(3) meters in magnitude and is directed from the initial position to the final position. The correct answer choice is B.

A Particle Goes from X = -2 M, Y =