A 10-turn ideal solenoid has an inductance of 3.5 mH.When the solenoid carries a current of 2.0 A the magnetic flux through each turn is: A)0 Wb B)3.5 * 10^-4 Wb C)7.0 * 10^-4 Wb D)7.0 *10^-3 Wb E)7.0 *10^-2 Wb

Question

Quizplus · Accepted Answer

The magnetic flux through each turn of the solenoid is given by the formula Phi = L*I/N, where Phi is the magnetic flux, L is the inductance, I is the current, and N is the number of turns. Plugging in the given values, we get Phi = (3.5 mH * 2.0 A) / 10 = 0.7 mWb = 7.0 F1F1F1S1F1F1F10 10^-4 Wb. Therefore, the correct answer is C.

A 10-Turn Ideal Solenoid Has an Inductance of 3