A geologist measures the Earth's electric field near the surface, and finds that equipotential lines 100 V apart are at a distance of 75 cm from each other.Assuming the electric field is uniform, what is its magnitude?

Question

Quizplus · Accepted Answer

The magnitude of the electric field (E) is given by the potential difference (ΔV) divided by the distance (d), so E = ΔV / d = 100 V / 0.75 m = 133.33 V/m, which rounds to 130 V/m as the closest answer.

A Geologist Measures the Earth's Electric Field near the Surface