An object is constrained by a cord to move in a circular path of radius 0.5m on a horizontal frictionless surface.The cord will break if its tension exceeds 16N.The maximum kinetic energy the object can have is:

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Quizplus · Accepted Answer

The maximum kinetic energy (KE) is related to the tension in the cord and the radius of the circular path. The tension (T) provides the centripetal force necessary for circular motion, which can be expressed as $T = \frac{mv^2}{r}$, where $m$ is the mass of the object, $v$ is its velocity, and $r$ is the radius of the circular path. The kinetic energy is given by $KE = \frac{1}{2}mv^2$. Substituting the expression for tension into the kinetic energy formula gives $KE = \frac{T \cdot r}{2}$. Given that $T = 16N$ and $r = 0.5m$, the maximum kinetic energy is $KE = \frac{16N \cdot 0.5m}{2} = 4J$.

An Object Is Constrained by a Cord to Move in a Circular