A particle moves 5 m in the positive x direction while being acted upon by a constant force = (4 N)+ (2 N)- (4 N).The work done on the particle by this force is:

Question

Quizplus · Accepted Answer

The work done by a force is calculated as the dot product of the force vector and the displacement vector. Here, the force vector is (4 N, 2 N, -4 N) and the displacement vector is (5 m, 0, 0). The dot product is (4 N * 5 m) + (2 N * 0) + (-4 N * 0) = 20 J.

A Particle Moves 5 M in the Positive X Direction