A drag racing car starts from rest at t = 0 and moves along a straight line with velocity given by v = bt², where b is a constant.The expression for the distance traveled by this car from its position at t = 0 is: A)bt³ B)bt³/3 C)4bt² D)3bt² E)bt^3/2

Question

Quizplus · Accepted Answer

The distance traveled by the car can be found by integrating the velocity function with respect to time. Given $v = bt^2$, the integral of $v$ with respect to $t$ gives the displacement function $s(t) = \frac{b}{3}t^3 + C$. Since the car starts from rest at $t = 0$, the constant $C = 0$, resulting in $s(t) = \frac{b}{3}t^3$, which matches option B.

A Drag Racing Car Starts from Rest at T =