When a metal object is dropped into cold water,it releases 4,715 J of energy to its surroundings,and its temperature decreases from 100.0 °C to 20.0 °C.The mass of the object is 420 grams.What is the specific heat of this material?

Question

Quizplus · Accepted Answer

We can use the formula q = m*c*ΔT, where q is the heat released, m is the mass, c is the specific heat, and ΔT is the change in temperature.

We are given q = 4,715 J, m = 420 g, ΔT = (100.0 - 20.0) = 80.0 °C.

Substituting these values, we get:

4,715 = (420) * c * 80.0

Solving for c, we get:

c = 0.140 J/g·°C

Therefore, the specific heat of this material is 0.140 J/g·°C. The correct answer is (C).

When a Metal Object Is Dropped into Cold Water,it Releases