Consider the following reaction: Fe + Br₂ $\rightarrow$ FeBr₂
If 38.6 grams of iron react with an excess of bromine gas,what mass of FeBr₂ can form?
(FeBr₂ = 215.65 g/mol)

Question

Consider the following reaction: Fe + Br₂ $\rightarrow$ FeBr₂ If 38.6 grams of iron react with an excess of bromine gas,what mass of FeBr₂ can form? (FeBr₂ = 215.65 g/mol)

Quizplus · Accepted Answer

To find the mass of FeBr2 that can form, first calculate the moles of Fe using its molar mass (55.85 g/mol). Then, since the reaction likely shows a 1:1 mole ratio between Fe and FeBr2, use the moles of Fe to find the mass of FeBr2. For 38.6 g of Fe: Moles of Fe = 38.6 g / 55.85 g/mol ≈ 0.691 mol. Mass of FeBr2 = 0.691 mol × 215.65 g/mol ≈ 149 g.

Consider the Following Reaction: Fe + Br2 →\rightarrow→ FeBr2 If 38

Consider the Following Reaction: Fe + Br₂ $\rightarrow$ FeBr₂
If 38