Consider an electrochemical cell consisting of zinc and nickel half-cells.Use the partial activity series included to determine the direction in which the electrons in the wire will flow. Zn $\rightarrow$ Zn²⁺ + 2e^-
Fe $\rightarrow$ Fe²⁺ + 2e^-
Co $\rightarrow$ Co²⁺ + 2e^-
Ni $\rightarrow$ Ni²⁺ + 2e^-
Cu $\rightarrow$ Cu²⁺ + 2e^-

Question

Consider an electrochemical cell consisting of zinc and nickel half-cells.Use the partial activity series included to determine the direction in which the electrons in the wire will flow. Zn

\rightarrow

Zn²⁺ + 2e^-
Fe

\rightarrow

Fe²⁺ + 2e^-
Co

\rightarrow

Co²⁺ + 2e^-
Ni

\rightarrow

Ni²⁺ + 2e^-
Cu

\rightarrow

Cu²⁺ + 2e^-

Quizplus · Accepted Answer

In an electrochemical cell, electrons flow from the anode to the cathode. Zinc is more reactive than nickel, meaning it more readily loses electrons (oxidation) and thus serves as the anode. Nickel, being less reactive, gains electrons (reduction) and serves as the cathode. Therefore, electrons flow from the zinc anode to the nickel cathode.

Consider an Electrochemical Cell Consisting of Zinc and Nickel Half-Cells →\rightarrow→

Consider an Electrochemical Cell Consisting of Zinc and Nickel Half-Cells $\rightarrow$