Consider the following equation: Zn (s)+ 2 HCl (aq)$\rightarrow$ ZnCl₂ (aq)+ H₂ (g) A 50-mL solution of 2.5-M HCl that completely reacts with zinc metal will produce _____ moles of ZnCl₂.

Question

Quizplus · Accepted Answer

First, we need to use stoichiometry to determine how many moles of Zn will react with 2.5 M of HCl:

2.5 mol HCl/L x 0.050 L = 0.125 mol HCl

From the balanced chemical equation, we see that 1 mole of Zn reacts with 2 moles of HCl to produce 1 mole of ZnCl2:

1 mol Zn : 2 mol HCl : 1 mol ZnCl2

So, the number of moles of ZnCl2 produced will be half of the number of moles of HCl used:

0.125 mol HCl / 2 = 0.063 mol ZnCl2

Therefore, the answer is B) 0.063.

Consider the Following Equation: Zn (S)+ 2 HCl (Aq) →\rightarrow→ ZnCl2 (Aq)+ H2 (G) a 50-ML Solution of 2

Consider the Following Equation: Zn (S)+ 2 HCl (Aq) $\rightarrow$ ZnCl₂ (Aq)+ H₂ (G)
a 50-ML Solution of 2