A sample of lead releases 221 kJ of heat when freezing.What is the mass of the sample? Δ H_fus = 23 J/g

Question

Quizplus · Accepted Answer

We can use the equation: Q = mΔH_fus Where Q is the heat released, m is the mass of the sample, and ΔH_fus is the heat of fusion. We first need to convert the heat of fusion to the same units as Q: ΔH_fus = 23 J/g = 23,000 J/kg Plugging in the given values, we have: 221 kJ = m × 23,000 J/kg Solving for m: m = 221,000 J / (23,000 J/kg) = 9.6 kg Therefore, the best choice is B) 9.6 g.

A Sample of Lead Releases 221 KJ of Heat When