The reaction 2 Sb + 3 Cl₂ $\rightarrow$ 2 SbCl₃ has an 88.3% yield.If 4.07 g of SbCl₃ is desired,what mass of chlorine should be used?

Question

Quizplus · Accepted Answer

The balanced equation is 2 Sb + 3 Cl₂ → 2 SbCl₃. The molar mass of SbCl₃ is 228.11 g/mol. The number of moles of SbCl₃ desired is 4.07 g / 228.11 g/mol = 0.0178 mol. The number of moles of Cl₂ required is 3/2 * 0.0178 mol = 0.0267 mol. The molar mass of Cl₂ is 70.90 g/mol. The mass of Cl₂ required is 0.0267 mol * 70.90 g/mol = 1.89 g.

The Reaction 2 Sb + 3 Cl2 →\rightarrow→ 2 SbCl3 Has an 88

The Reaction 2 Sb + 3 Cl₂ $\rightarrow$ 2 SbCl₃ Has an 88