Cu₂HgI₄ Is Prepared According to the Equation 2 CuI $\rightarrow$ Cu₂HgI₄

Cu₂HgI₄ is prepared according to the equation 2 CuI + HgI₂ $\rightarrow$ Cu₂HgI₄.When 2.00 g of each reactant are used,which one is the limiting reactant?

A) Both reactants are limiting
B) This reaction has no limiting reactant
C) CuI
D) HgI₂
E) Cu₂HgI₄