The following reaction occurs in aqueous acid solution: NO₃^- + I^- $\rightarrow$ IO₃^- + NO₂
The oxidation state of iodine in IO₃^- is

Question

The following reaction occurs in aqueous acid solution: NO₃^- + I^- $\rightarrow$ IO₃^- + NO₂ The oxidation state of iodine in IO₃^- is

Quizplus · Accepted Answer

In the given species, O and S have a known oxidation state of -2 and +6, respectively. Therefore, we can set up the following equation: (-2 x 2) + (x) + (-2) + (-1 x 2) + (-1) + (-1) + (-1) + (-1) + (-1) = 0 where x is the oxidation state of iodine. Simplifying, we get: x - 10 = 0 x = +10 However, the highest possible oxidation state of iodine is +7, so this answer is not possible. Therefore, we must consider that iodine is in a lower oxidation state and is being oxidized in the reaction. The product NO₂ has iodine in the +5 oxidation state, so it must have been oxidized from a lower state. Therefore, the oxidation state of iodine in IO₃^- is +3 (choice D).

The Following Reaction Occurs in Aqueous Acid Solution: NO3- →\rightarrow→ IO3- + NO2 the Oxidation State of Iodine in IO3-

The Following Reaction Occurs in Aqueous Acid Solution: NO₃^- $\rightarrow$ IO₃^- + NO₂
the Oxidation State of Iodine in IO₃^-