In the following reaction, which element is oxidized? 8NaI + 5H₂SO₄ $\rightarrow$4I₂ + H₂S + 4Na₂SO₄ + 4H₂O

Name: In the following reaction, which element is oxidized? 8NaI + 5H 2 SO 4 $\rightarrow$4I 2 + H 2 S + 4Na 2 SO 4 + 4H 2 O
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In the reaction, NaI is reacting with F2, leading to the formation of NaF and I2. Iodine (I) is reduced from a -1 oxidation state in NaI to a 0 oxidation state in I2, indicating that it has gained electrons and is therefore the element that is oxidized.

In the Following Reaction, Which Element Is Oxidized? 8NaI →\rightarrow→ 4I2 + H2S + 4Na2SO4 + 4H2O A) Sodium B)

In the Following Reaction, Which Element Is Oxidized? 8NaI $\rightarrow$ 4I₂ + H₂S + 4Na₂SO₄ + 4H₂O
A) Sodium
B)