You have 3.00 L of a 3.00 M solution of NaCl(aq) called solution A. You also have 2.00 L of a 1.84 M solution of AgNO₃(aq) called solution B. You mix these solutions together, making solution C. Calculate the concentration (in M) of ions in solution C.

Question

Quizplus · Accepted Answer

Since NaCl dissociates into Na+ and Cl- ions and AgNO3 dissociates into Ag+ and NO3- ions, the only ion of interest in this problem is NO3-. When the two solutions are mixed, the NO3- ion concentrations will simply add together:

[NO3-]C = [NO3-]A + [NO3-]B

[NO3-]A = 3.00 M x 2 = 6.00 mol

[NO3-]B = 1.84 M x 2 = 3.68 mol

[NO3-]C = 6.00 mol + 3.68 mol = 9.68 mol

Now we need to convert this to concentration by dividing by the total volume of the mixture:

[NO3-]C = 9.68 mol / 5.00 L = 1.94 M

Since the question asks for the concentration of AgNO3 ions (NO3-), the correct answer is B.

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