Fe₂O₃ (molar mass = 159.7 g/mol) reacts with CO (molar mass = 28.0 g/mol) according to the equation When 470.0 g Fe₂O₃ reacts with excess CO, what number of moles of Fe (iron) is produced?

Question

Quizplus · Accepted Answer

1. Write the balanced chemical equation: Fe₂O₃ + 4CO → 4CO2 +Fe₂ + 2Fe 2. Calculate the number of moles of Fe₂O₃: molar mass Fe₂O₃ = 159.7 g/mol n = m/M = 470.0 g / 159.7 g/mol = 2.945 mol Fe₂O₃ 3. Use stoichiometry to find the number of moles of Fe produced: From the balanced chemical equation, 1 mol Fe₂O₃ reacts with 2 mol Fe to produce 1 mol Fe: 2 mol Fe / 1 mol Fe₂O₃ n(Fe) = n(Fe₂O₃) x (2 mol Fe / 1 mol Fe₂O₃) = 5.89 mol Fe Round to three significant figures: 5.886 mol Fe.

Fe2O3 (Molar Mass = 159

Fe₂O₃ (Molar Mass = 159