When 10.0 mol of calcium metal is reacted with 3.9 mol of oxygen gas, how much calcium oxide is produced?

Question

Quizplus · Accepted Answer

The balanced chemical equation for the reaction is:

2Ca + O2 → 2CaO

According to the stoichiometry of the equation, 2 moles of calcium react with 1 mole of oxygen to produce 2 moles of calcium oxide. Therefore, to determine the amount of calcium oxide produced, we need to find the limiting reactant first.

- Calcium: 10.0 mol
- Oxygen: 3.9 mol

The stoichiometric ratio of calcium to oxygen is 2:1. Therefore, if all the calcium reacts, we would need 2 × 10.0 = 20.0 mol of oxygen. Since we only have 3.9 mol of oxygen, it is the limiting reactant. This means that all the oxygen will be used up before all the calcium is consumed. We can calculate the amount of calcium oxide produced as follows:

3.9 mol O2 × (2 mol CaO/1 mol O2) = 7.8 mol CaO

Therefore, the answer is C) 7.8 mol.

When 100 Mol of Calcium Metal Is Reacted with 3