Ammonia reacts with oxygen to form nitrogen dioxide and water according to the following equation: You react ammonia and oxygen, and at the end of the experiment you find that you produced 23.0 g of water and have 8.52 g of ammonia left over. Determine the mass of oxygen reacted.

Question

Ammonia reacts with oxygen to form nitrogen dioxide and water according to the following equation:  You react ammonia and oxygen, and at the end of the experiment you find that you produced 23.0 g of water and have 8.52 g of ammonia left over. Determine the mass of oxygen reacted.

Quizplus · Accepted Answer

First, we need to find the amount of ammonia that reacted by subtracting the amount left over from the initial amount:

Initial amount of ammonia - Amount of ammonia left over = Amount of ammonia reacted
x - 8.52 g = amount of ammonia reacted

Next, we need to use stoichiometry to find the amount of oxygen that reacted based on the amount of water produced. From the balanced equation, we can see that the ratio of ammonia to water is 4:6, which simplifies to 2:3:

2 NH3 + 3 O2 -> 2 NO + 3 H2O

So for every 3 moles of water produced, we need 2 moles of ammonia and 3 moles of oxygen.

We can use the amount of water produced to calculate the amount of oxygen needed:

23.0 g H2O x (1 mol H2O / 18.015 g H2O) x (3 mol O2 / 3 mol H2O) = 3.20 mol O2

Finally, we can use the amount of ammonia reacted and the stoichiometric ratio to find the amount of oxygen that reacted:

x - 8.52 g NH3 x (1 mol NH3 / 17.031 g NH3) x (3 mol O2 / 2 mol NH3) = 0.901 mol O2

Now that we know the amount of oxygen that reacted, we can use its molar mass to calculate its mass:

0.901 mol O2 x 31.998 g/mol O2 = 28.9 g O2

Therefore, the correct answer is E) 47.7 g of oxygen.

Ammonia Reacts with Oxygen to Form Nitrogen Dioxide and Water