Calculate the mass of 3.663 moles of silver nitrate.

Question

Quizplus · Accepted Answer

The molar mass of silver nitrate (AgNO3) can be calculated as follows: 
Ag = 107.87 g/mol 
N = 14.01 g/mol 
O3 = 3 x 16.00 g/mol = 48.00 g/mol 
Therefore, the molar mass of AgNO3 is: 
107.87 + 14.01 + 48.00 = 169.88 g/mol

To determine the mass of 3.663 moles of AgNO3, we can use the following formula: 
Mass = molar mass x number of moles 
Mass = 169.88 g/mol x 3.663 mol 
Mass = 622.4 g

Therefore, the answer is B: 622.4 g.

Calculate the Mass of 3