An object with an initial velocity of 12 m/s west experiences a constant acceleration of 4 m/s² west for 3 seconds.During this time the object travels a distance of: A)18 m B)24 m C)36 m D)54 m E)144 m

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Quizplus · Accepted Answer

The object's final velocity can be calculated using the formula $v = u + at$, where $v$ is the final velocity, $u$ is the initial velocity, $a$ is the acceleration, and $t$ is the time. Substituting the given values, we get $v = 12\,m/s + (4\,m/s^2 \times 3\,s) = 24\,m/s$. The distance traveled can be calculated using the formula $s = ut + \frac{1}{2}at^2$, where $s$ is the distance. Substituting the given values, we get $s = (12\,m/s \times 3\,s) + \frac{1}{2}(4\,m/s^2 \times 9\,s^2) = 36\,m + 18\,m = 54\,m$.

An Object with an Initial Velocity of 12 M/s West