An object is at rest at x = 0 m, y = 0 m.It accelerates at a rate of (−3.2 m/s²) + (8.6 m/s²) .After accelerating for 4.7 seconds its coordinates are: A)x = −15 m, y = 40 m B)x = −35 m, y = 95 m C)x = −24 m, y = 170 m D)x = −70 m, y = 190 m E)x = −48 m, y = 340 m

Question

Quizplus · Accepted Answer

The motion can be divided into x and y components as:
ax = -3.2 m/s^2
ay = 8.6 m/s^2

Using the equations of motion:
x = ut + 1/2 at^2
y = vt + 1/2 at^2

At t = 4.7 s,
x = 0 + 1/2 (-3.2) (4.7)^2 = -35 m
y = 0 + 1/2 (8.6) (4.7)^2 = 95 m

Therefore, the object's coordinates after 4.7 seconds are x = -35 m and y = 95 m, which matches with option B.

An Object Is at Rest at X = 0 M