A forward horizontal force of 12 N is used to pull a 240-N crate at constant velocity across a horizontal floor.The coefficient of friction is:
A)0.5
B)0.05
C)2
D)0.2
E)20

Question

Quizplus · Accepted Answer

The force of friction equals the applied force when moving at constant velocity. The frictional force is 12 N, and the normal force is 240 N. The coefficient of friction (μ) is calculated as μ = frictional force / normal force = 12 N / 240 N = 0.05.

A Forward Horizontal Force of 12 N Is Used to Pull