A bureau rests on a rough horizontal surface ( = 0.50, = 0.40).A constant horizontal force, just sufficient to start the bureau in motion, is then applied.The acceleration of the bureau is: A)0 m/s² B)0.98 m/s² C)3.9 m/s² D)4.9 m/s² E)8.8 m/s²

Question

Quizplus · Accepted Answer

The acceleration can be calculated using Newton's second law, $F = ma$, where $F$ is the net force applied, $m$ is the mass of the object, and $a$ is the acceleration. When the bureau starts moving, the force of kinetic friction ($F_{k}$) acts against the motion. The force of kinetic friction is given by $F_{k} = \mu_{k}N$, where $\mu_{k} = 0.40$ is the coefficient of kinetic friction and $N$ is the normal force, which equals the weight of the bureau if the surface is horizontal. Since the question does not provide the mass of the bureau or the force applied, but asks for the acceleration right after the bureau starts moving, we can infer that the net force acting on the bureau is now the difference between the applied force and the force of kinetic friction. Given the information, we cannot calculate the exact value of acceleration without knowing the mass or the applied force. However, the correct approach involves understanding that the acceleration is determined by the net force (applied force minus friction force) and the mass of the bureau. Since the specific numbers are not provided, the correct answer must be inferred from understanding the principles involved rather than from a direct calculation. The mention of specific acceleration values without providing mass or force implies a misunderstanding of the question's requirements or a typographical error in the question.

A Bureau Rests on a Rough Horizontal Surface ( =