An object of mass 1 kg is whirled in a horizontal circle of radius 0.5 m at a constant speed of 2 m/s.The work done on the object during one revolution is:

Question

Quizplus · Accepted Answer

The work done on an object is given by the formula:
Work = force x distance x cos(theta)
In this case, the force acting on the object is towards the center of the circle and is given by the formula:
Force = (mass x velocity^2) / radius

Plugging in the given values, we get:
Force = (1 kg x 2 m/s^2) / 0.5 m = 4 N

Since the force is perpendicular to the displacement of the object (which is along the circle), the angle theta between force and displacement is 90 degrees. Therefore, cos(theta) = 0.

Thus, the work done on the object is:
Work = 4 N x 2piR x 0 = 0 J

Therefore, the best choice is A) 0 J.

An Object of Mass 1 Kg Is Whirled in a Horizontal