When a thin uniform stick of mass M and length L is pivoted about its midpoint, its rotational inertia is ML²/12.When pivoted about a parallel axis through one end, its rotational inertia is: A)ML²/12 B)ML²/6 C)ML²/3 D)7ML²/12 E)13ML²/12

Question

Quizplus · Accepted Answer

According to the parallel axis theorem, the rotational inertia of a body about an axis parallel to an axis passing through its center of mass is given by I = Icm + Md^2, where Icm is the rotational inertia about the center of mass, M is the mass of the object, and d is the perpendicular distance between the two axes. In this case, the rotational inertia about the center of mass is ML²/12, and the perpendicular distance between the two axes is L/2. Therefore, the rotational inertia about the end axis is I = ML²/12 + M(L/2)^2, which simplifies to ML²/3. Hence, the correct answer is option C.

When a Thin Uniform Stick of Mass M and Length