A disk with a rotational inertia of 2.0 kg.m² and a radius of 0.40 m rotates on a frictionless fixed axis perpendicular to the disk faces and through its center.A force of 5.0 N is applied tangentially to the rim.The angular acceleration of the disk is: A)0.40 rad/s² B)0.60 rad/s² C)1.0 rad/s² D)2.5 rad/s² E)10 rad/s²

Question

Quizplus · Accepted Answer

We can use the formula:
τ = Iα
where τ is the torque applied, I is the rotational inertia, and α is the angular acceleration.

We are given τ = 5.0 N, and I = 2.0 kg·m². Solving for α, we get:

α = τ / I = 5.0 N / (2.0 kg·m²) = 2.5 rad/s²

Therefore, the angular acceleration of the disk is 2.5 rad/s², which is closest to choice C.

A Disk with a Rotational Inertia of 2