A particle is in simple harmonic motion along the x axis.The amplitude of the motion is x_m.When it is at x = x₁, its kinetic energy is K = 5 J and its potential energy (measured with U = 0 at x = 0)is U = 3 J.When it is at x = -1/2 x_m, its total energy is: A)0 J B)3 J C)4 J D)5 J E)8 J

Question

Quizplus · Accepted Answer

The total energy in simple harmonic motion is conserved and is the sum of kinetic and potential energy. At x = x₁, the total energy is K + U = 5 J + 3 J = 8 J. Since energy is conserved, at any other position, including x = -1/2 x₁, the total energy remains 8 J.

A Particle Is in Simple Harmonic Motion Along the X