The intensity of sound wave A is 100 times that of sound wave B.Relative to wave B the sound level of wave A is:
A)-2 db
B)+2 db
C)+10 db
D)+20 db
E)+100 db

Question

Quizplus · Accepted Answer

To determine the sound level difference between two waves, we use the formula:

ΔL = 10log(I2/I1)

where ΔL is the difference in sound level, I1 is the intensity of the reference wave (in this case, wave B) and I2 is the intensity of the other wave (in this case, wave A).

Plugging in the values given, we get:

ΔL = 10log(I2/I1)
ΔL = 10log(100)
ΔL = 10(2)
ΔL = 20

Therefore, the sound level difference between wave A and wave B is +20dB.

The Intensity of Sound Wave a Is 100 Times That