A slab of material has area A, thickness L, and thermal conductivity k.One of its surfaces (P)is maintained at temperature T₁ and the other surface (Q)is maintained at a lower temperature T₂.The rate of heat flow from P to Q is:

Question

Quizplus · Accepted Answer

The rate of heat flow is given by Q = kA(T1 - T2)/L, where T1 is the temperature of the hot surface, T2 is the temperature of the cold surface, A is the area of the slab, L is the thickness of the slab, and k is the thermal conductivity of the material. Rearranging this equation, we get Q = (k/L)A(T1 - T2), which is equivalent to choice C.

A Slab of Material Has Area A, Thickness L, and Thermal