Let k be the Boltzmann constant.If the configuration of molecules in a gas changes from one with a multiplicity of M₁ to one with a multiplicity of M₂, then entropy changes by: A)"$\Delta$S = 0" B)"$\Delta$S = k(M₂ - M₁)" C)"$\Delta$S = kM₂/M₁" D)"$\Delta$S = k ln(M₂M₁)" E)"$\Delta$S = k ln(M₂/M₁)"

Question

Quizplus · Accepted Answer

The entropy change can be calculated using the formula ΔS = k ln(W2/W1), where W1 and W2 are the initial and final multiplicities of the system, respectively. Therefore, the correct choice is E: "ΔS = k ln(M₂/M₁)".

Let K Be the Boltzmann Constant Δ\DeltaΔ S = 0" B) Δ\DeltaΔ

Let K Be the Boltzmann Constant $\Delta$ S = 0"
B) $\Delta$