A particle with a charge of 5 *10^-6 C and a mass of 20 g moves uniformly with a speed of 7 m/s in a circular orbit around a stationary particle with a charge of -5 * 10^-6 C.The radius of the orbit is:

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Quizplus · Accepted Answer

The radius of the orbit can be found using the formula for the centripetal force acting on a charged particle moving in a circular path due to the electrostatic force between two charges, which is given by $F = \frac{k \cdot |q_1 \cdot q_2|}{r^2}$, where $F$ is the centripetal force, $k$ is Coulomb's constant ($8.987 \times 10^9 \, \text{Nm}^2/\text{C}^2$), $q_1$ and $q_2$ are the charges of the particles, and $r$ is the radius of the orbit. The centripetal force can also be expressed as $F = \frac{m \cdot v^2}{r}$, where $m$ is the mass of the moving particle, and $v$ is its velocity. Equating the two expressions for $F$ and solving for $r$ gives the radius of the orbit. Given that both charges are $5 \times 10^{-6} \, \text{C}$, the mass of the moving particle is $20 \, \text{g} = 0.02 \, \text{kg}$, and its velocity is $7 \, \text{m/s}$, substituting these values into the formula and solving for $r$ yields a radius of approximately $0.23 \, \text{m}$.

A Particle with a Charge of 5 *10-6 C and a Mass

A Particle with a Charge of 5 *10^-6 C and a Mass