Charge is placed on the surface of a 2.7-cm radius isolated conducting sphere.The surface charge density is uniform and has the value 6.9 * 10^-6 C/m².The total charge on the sphere is: A)5.7 *10^-10 C B)1.6*10^-8 C C)3.2 * 10^-8 C D)6.3 *10^-8 C E)7.5 * 10^-⁴ C

Question

Quizplus · Accepted Answer

The total charge on the sphere can be found by multiplying the surface charge density with the surface area of the sphere:

Q = ρA

where Q is the total charge, ρ is the surface charge density, and A is the surface area.

The surface area of a sphere is given by:

A = 4πr^2

where r is the radius of the sphere.

Substituting the given values, we get:

Q = (6.9 x 10^-6 C/m^2) x 4π(0.027 m)^2 = 6.3 x 10^-8 C

Therefore, the answer is D, 6.3 x 10^-8 C.

Charge Is Placed on the Surface of a 2