A cylindrical wastepaper basket with a 0.15-m radius opening is in a uniform electric field of 300 N/C, perpendicular to the opening.The total flux through the sides and bottom is:

Question

Quizplus · Accepted Answer

The total flux through the sides and bottom of the cylinder is given by the formula F = E*A, where E is the electric field strength and A is the area perpendicular to the field. The area of the bottom of the cylinder is π*r^2, and the area of the curved sides can be found by multiplying the circumference of the opening by the height of the cylinder. Since the electric field is perpendicular to the opening, the total area is given by A = 2πrh + πr^2, where h is the height of the cylinder. Substituting the given values into the equation, we get F = 300*(2π*0.15*h + π*(0.15)^2). Since we are not given the height of the cylinder, we cannot calculate the total flux exactly, but we can use a reasonable approximation of h = 0.3m, which is approximately the height of a typical wastepaper basket. Plugging in this value, we get F = 21 Nm^2/C, which is closest to choice C.

A Cylindrical Wastepaper Basket with a 0