A 5-cm radius conducting sphere has a charge density of 2 * 10^-6 C/m² on its surface.Its electric potential, relative to the potential far away, is:

Question

Quizplus · Accepted Answer

The electric potential of a conducting sphere is given by:V = k * Q / rwhere:k is Coulomb's constant (8.98755 × 10^9 N⋅m^2/C^2)Q is the charge on the sphere (2 × 10^-6 C)r is the radius of the sphere (5 cm = 0.05 m)Plugging in these values, we get:V = (8.98755 × 10^9 N⋅m^2/C^2) * (2 × 10^-6 C) / (0.05 m) = 3.595 × 10^4 VTherefore, the electric potential of the sphere, relative to the potential far away, is 3.595 × 10^4 V, which is closest to choice A) 1.1 F1F1F1S1 *F1F1F10 10⁴ V.

A 5-Cm Radius Conducting Sphere Has a Charge Density of 2