A certain capacitor has a capacitance of 5.0 $\mu$F.After it is charged to 5 $\mu$C and isolated, the plates are brought closer together so its capacitance becomes 10 $\mu$F.The work done by the agent is about: A)"0 J" B)"1.25 * 10^-6 J" C)"-1.25 * 10^-6 J" D)"8.3 * 10^-7 J" E)"-8.3 *10^-7 J"

Question

Quizplus · Accepted Answer

When the plates are brought closer, the capacitance increases, and the energy stored in the capacitor decreases. The work done by the agent is negative, equal to the decrease in energy, which is -1.25 x 10^-6 J.

A Certain Capacitor Has a Capacitance of 5 μ\muμ FAfter It Is Charged to 5

A Certain Capacitor Has a Capacitance of 5 $\mu$ FAfter It Is Charged to 5