A current of 0.3 A passes through a lamp for 2 minutes using a 6 V power supply.The energy dissipated by this lamp during the 2 minutes is:
A)1.8 J
B)12 J
C)20 J
D)36 J
E)216 J

Question

Quizplus · Accepted Answer

The energy dissipated can be calculated using the formula $E = P \times t$, where $E$ is energy in joules, $P$ is power in watts, and $t$ is time in seconds. First, calculate power using $P = IV$, where $I$ is current in amperes and $V$ is voltage in volts. Here, $P = 0.3 \, \text{A} \times 6 \, \text{V} = 1.8 \, \text{W}$. The time needs to be in seconds, so $2 \, \text{minutes} = 120 \, \text{seconds}$. Thus, $E = 1.8 \, \text{W} \times 120 \, \text{s} = 216 \, \text{J}$.

A Current of 0