A solenoid is 3.0 cm long and has a radius of 0.50 cm.It is wrapped with 500 turns of wire carrying a current of 2.0 A.The magnetic field at the center of the solenoid is: A)9.9 * 10^-8 T B)1.3 * 10^-3 T C)4.2 * 10^-2 T D)16 T E)20 T

Question

Quizplus · Accepted Answer

The magnetic field inside a solenoid is given by B=μ₀nI, where μ₀ is the magnetic constant, n is the number of turns per unit length, and I is the current. 
In this case, n=N/L, where N is the total number of turns and L is the length of the solenoid. 
So, n=500/(3 cm) = 166.67 turns/cm. 
Substituting into the equation, we get B = μ₀nI = (4π×10⁻⁷ T·m/A)×(166.67 turns/cm)×(2.0 A) = 1.33×10⁻² T = 1.3×10⁻² T. 
Therefore, the answer is C.

A Solenoid Is 3