As a loop of wire with a resistance of 10 $\Omega$ moves in a non-uniform magnetic field, it loses kinetic energy at a uniform rate of 5 mJ/s.The induced emf in the loop is:
A)0 V
B)0.22 V
C)0.28 V
D)2.0 V
E)cannot be calculated from the given data

Question

Quizplus · Accepted Answer

The induced emf ($\epsilon$) in the loop can be calculated using the power loss due to the resistance in the loop. The power ($P$) lost is given by $P = \frac{\epsilon^2}{R}$, where $R$ is the resistance. Given that $P = 5 mJ/s = 5 \times 10^{-3} W$ and $R = 10 \Omega$, we can rearrange the formula to solve for $\epsilon$: $\epsilon = \sqrt{P \times R} = \sqrt{5 \times 10^{-3} \times 10} = \sqrt{0.05} = 0.2236 V$, which rounds to 0.22 V.

As a Loop of Wire with a Resistance of 10 Ω\OmegaΩ

As a Loop of Wire with a Resistance of 10 $\Omega$