An 8.0-mH inductor and a 2.0- $\Omega$ resistor are wired in series to a 20-V ideal battery.A switch in the circuit is closed at time t = 0, at which time the current is zero.After a long time the current in the resistor and the current in the inductor are:
A)0 A, 0 A
B)10 A, 10 A
C)2.5 A, 2.5 A
D)10 A, 2.5 A
E)10 A, 0 A

Question

Quizplus · Accepted Answer

After a long time, the inductor acts like a short circuit (its reactance becomes zero), so the current in the circuit is determined only by the resistor. Using Ohm's Law (V = IR), the current I = V/R = 20V/2Ω = 10 A. This current flows through both the resistor and the inductor.

An 80-MH Inductor and a 2 Ω\OmegaΩ Resistor Are Wired in Series to a 20-V Ideal Battery

An 80-MH Inductor and a 2 $\Omega$ Resistor Are Wired in Series to a 20-V Ideal Battery