Two coils have a mutual inductance of 3.5 mH.If the current in one coil is changing at a rate of 4.8 A/s, what is the emf induced in the second coil? A)7.3 x 10^-4 V B)0.017 V C)1400 V D)cannot tell without knowing the inductance of the second coil E)cannot tell without knowing the current in the second coil

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Quizplus · Accepted Answer

The emf induced in the second coil can be calculated using the formula: emf = M * (di/dt), where M is the mutual inductance and di/dt is the rate of change of current. Here, emf = 3.5 mH * 4.8 A/s = 0.0168 V, which is approximately 0.017 V.

Two Coils Have a Mutual Inductance of 3