Light with an intensity of 1 kW/m² falls normally on a surface with an area of 1 cm² and is completely absorbed.The force of the radiation on the surface is: A)3.3 * 10^-11 N B)1.7 * 10^-10 N C)3.3 *10^-10 N D)6.7 *10^-10 N E)1.0 * 10^-4 N

Question

Quizplus · Accepted Answer

First, we need to convert the intensity from kW/m² to W/m²:
1 kW/m² = 1000 W/m²
Next, we need to convert the surface area from cm² to m²:
1 cm² = 0.0001 m²
Therefore, the force of the radiation on the surface is:
(1000 W/m²) x (0.0001 m²) = 0.1 N
However, the question asks for the force in scientific notation, which can be written as:
1.0 x 10^-1 N
To convert this to the desired format (F x 10^-N), we need to express the force as a number between 1 and 10 and adjust the exponent accordingly. In this case, we can write:
1.0 x 10^-1 N = 0.33 x 10^-1 N
= 3.3 x 10^-2 N
Since the question asks for the answer in scientific notation with the format F x 10^-N, the best choice is C, which gives the force as 3.3 x 10^-10N.

Light with an Intensity of 1 KW/m2 Falls Normally on a Surface

Light with an Intensity of 1 KW/m² Falls Normally on a Surface