Light with an intensity of 1 kW/m² falls normally on a surface and is completely absorbed.The radiation pressure is: A)1 kPa B)3 *10¹¹ Pa C)1.7 *10^-6 Pa D)3.3*10^-6 Pa E)6.7 * 10^-6 Pa

Question

Quizplus · Accepted Answer

The radiation pressure is given by:

P = I/c

where I is the intensity and c is the speed of light. Plugging in the given values, we get:

P = (1 kW/m²)/(3×10⁸ m/s) = 3.33×10⁻⁶ Pa

This answer is closest to option D, which is 3.3×10⁻⁶ Pa.

Light with an Intensity of 1 KW/m2 Falls Normally on a Surface

Light with an Intensity of 1 KW/m² Falls Normally on a Surface