In a Young's double-slit experiment, light of wavelength 500 nm illuminates two slits which are separated by 1 mm.The separation between adjacent bright fringes on a screen 5 m from the slits is:
A)0.10 cm
B)0.25 cm
C)0.50 cm
D)1.0 cm
E)none of the above

Question

Quizplus · Accepted Answer

The separation between adjacent bright fringes, also known as fringe width ($y$), in a Young's double-slit experiment is given by the formula $y = \frac{\lambda D}{d}$, where $\lambda$ is the wavelength of the light, $D$ is the distance from the slits to the screen, and $d$ is the separation between the slits. Plugging in the given values: $y = \frac{500 \times 10^{-9} \text{ m} \times 5 \text{ m}}{1 \times 10^{-3} \text{ m}} = 2.5 \times 10^{-3} \text{ m} = 0.25 \text{ cm}$.

In a Young's Double-Slit Experiment, Light of Wavelength 500 Nm