Bragg's law for x-ray diffraction is 2d sin $\theta$ = m $\lambda$ , where $\theta$ is the angle between the incident beam and:
A)a reflecting plane of atoms
B)the normal to a reflecting plane of atoms
C)the scattered beam
D)the normal to the scattered beam
E)the refracted beam

Question

Bragg's law for x-ray diffraction is 2d sin $\theta$ = m $\lambda$ , where  $\theta$ is the angle between the incident beam and:
A)a reflecting plane of atoms
B)the normal to a reflecting plane of atoms
C)the scattered beam
D)the normal to the scattered beam
E)the refracted beam

Quizplus · Accepted Answer

Bragg's law describes the diffraction of X-rays from a crystal lattice. The angle between the incident beam and the reflecting plane of atoms is the angle that satisfies Bragg's law.

Bragg's Law for X-Ray Diffraction Is 2d Sin θ\thetaθ = M λ\lambdaλ

Bragg's Law for X-Ray Diffraction Is 2d Sin $\theta$ = M $\lambda$